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Chegu Khairi

Kebarangkalian Mudah

Lupa Menambah Jumlah Keseluruhan dalam Kebarangkalian

Forgetting Total Items Increase in Probability

Forgetting Total Items Increase in Probability

Apabila manik merah ditambah ke dalam kotak, jumlah keseluruhan manik juga bertambah dengan bilangan yang sama. Jika x biji manik merah ditambah, kebarangkalian baharu ialah 1/2 = (2+x)/(10+x). Menyelesaikan persamaan ini memberikan x = 6 biji manik yang perlu ditambah, dan bukannya 8 biji manik.

When red beads are added to a box, the total number of beads also increases by the same amount. If x red beads are added, the new probability is 1/2 = (2+x)/(10+x). Solving this linear equation yields x = 6 beads to be added, rather than stating a total of 8 beads.

Kertas sebenar, sudah ditanda

The marked scripts

The working states 8 beads are needed overall but fails to subtract the 2 existing red beads.
Pengiraan menyatakan 8 biji manik diperlukan tetapi tidak menolak 2 biji manik merah sedia ada. The working states 8 beads are needed overall but fails to subtract the 2 existing red beads.
The denominator is not increased by the number of new beads when the numerator is increased.
Penyebut tidak ditambah dengan bilangan manik baharu apabila pengangka ditambah. The denominator is not increased by the number of new beads when the numerator is increased.
The equation is set up correctly but the subsequent algebraic solving steps are incorrect.
Persamaan dibentuk dengan betul tetapi langkah penyelesaian algebra seterusnya adalah salah. The equation is set up correctly but the subsequent algebraic solving steps are incorrect.

Yang salah

What went wrong

P(merah) = (2+x)/10 = 1/2
2 + x = 5
x = 3
P(red) = (2+x)/10 = 1/2
2 + x = 5
x = 3

Yang betul

The correct working

P(merah) = (2+x)/(10+x) = 1/2
2(2 + x) = 1(10 + x)
4 + 2x = 10 + x
2x - x = 10 - 4
x = 6
P(red) = (2+x)/(10+x) = 1/2
2(2 + x) = 1(10 + x)
4 + 2x = 10 + x
2x - x = 10 - 4
x = 6

Kenapa ramai buat silap ini

Why this happens

Kesilapan berlaku apabila penyebut tidak ditambah dengan x apabila pengangka ditambah x, atau apabila jumlah manik merah baharu (8) ditemui tetapi tidak ditolak dengan 2 biji manik merah sedia ada.

Errors occur when the denominator is not increased by x alongside the numerator, or when the new target number of red beads (8) is found without subtracting the 2 original red beads.

Markah yang hilang

Marks lost

Kehilangan markah jawapan akhir kerana tidak menolak bilangan asal.

Loss of final answer mark for failing to subtract the original quantity.

Chegu Khairi menanda kerja ini setiap minggu

Chegu Khairi marks this every week

Kerja rumah ditanda pada hari yang sama dan dibincangkan dalam kelas berikutnya, jadi kesalahan sebegini dapat diperbetulkan semasa latihan dan bukan berlaku semasa peperiksaan.

Homework is marked the same day and discussed in the next class, so a mistake like this one gets corrected during practice rather than happening in the exam.

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